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5a^2-33a+28=0
a = 5; b = -33; c = +28;
Δ = b2-4ac
Δ = -332-4·5·28
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-23}{2*5}=\frac{10}{10} =1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+23}{2*5}=\frac{56}{10} =5+3/5 $
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